Monthly Archives: March 2019

JEE Main 2019 Result By April 30

JEE Advanced 2019: IIT Roorkee, which is responsible for conducting JEE Advanced 2019 exam, has released the application dates and other important details for the exam. JEE Advanced exam is the entrance examination for admission to IITs. Only the top 2,24,000 candidates who qualify in JEE Main exam are eligible to sit in the JEE Advanced exam. This year JEE Main exam is being conducted twice so students get two chances to become eligible for the JEE Advanced exam.

The admit cards for the second JEE Main 2019 exam have been released already and the exam will be conducted in April. After the exams are over, National Testing Agency (NTA) will release the JEE Main 2 result by April 30, 2019.

Students who qualify for the JEE Advanced 2019 exam will have to register separately for the exam. The registration for JEE Advanced 2019 exam will begin on May 3, 2019 and conclude on May 9, 2019. Students will be allowed to pay application fee till May 10, 2019.

The admit cards for applicants will be released on May 20, 2019 and will be available for downloading till May 27, 2019.

The exam will be conducted on May 27, 2019. After the conclusion of exam, students will be sent their candidate responses from May 29 to June 1, 2019.

The provisional answer key for JEE Advanced exam will be released on June 4, 2019. Students will also be able to submit any objection on the answer key from June 4 to June 5, 2019. After resolving the objections submitted by students, the final result for JEE Advanced will be released on June 14, 2019.

for more detail about Jee Main 2019 Result – Click Here

Computer Basic Concepts problems

Question No. 1 What is data ? What is the output of data processing system ?

Answer Data are raw facts and figures. Data processing system transforms data into useful information.

Question No. 2 State the basic units of the computer , Name the submits that make up the CPU, and give the function of each of the units.

Answer The basic units of a computer are:

  1. Input Unit
  2. Central Processing Unit (CPU)
  3. Output Unit
  4. Memory

The CPU has two sub units : the control unit (CU) and the arithmetic logic unit (ALU).

The control unit controls the entire operation being carried out.

The ALU performs the arithmetic and logical operations.

Question No. 3 What is the funtion of memory ? What are its measuring units ?

Answer The memory temporarily holds the data and information during processing.

The smallest unit of memory is a byte (8 bits). A byte can store one character in binary form.

Other measuring units are kilobyte (KB) equal to 1024 (2) bytes, Megabyte (MB) equal to 1024 KB and Gigabyte (GB) equal to 1024 MB.

Learn Online Octal Number System CCC Course

The octal numeral system, or oct for short, is the base-8 number system, and uses the digits 0 to 7. Octal numerals can be made from binary numerals by grouping consecutive binary digits into groups of three (starting from the right). For example, the binary representation for decimal 74 is 1001010. Two zeroes can be added at the left: (00)1 001 010, corresponding the octal digits 1 1 2, yielding the octal representation 112.

Some importance of octal number system

The binary number system is an alternative to the decimal (10-base) number system that we use every day. Binary numbers are important because using them instead of the decimal system simplifies the design of computers and related technologies.

Learn Hexadecimal Number System Online CCC Course

Hexadecimal number system • The number system with base or radix digit is (16) is known as hexadecimal number system. • This system requires 16 digits to represent the number. • The first 10 digits are digits of the decimal system from 0 to 9 and remaining 6 digits are denoted by (A to F) which representing decimal values (10 to 15) where A=10, B=11, C=12, D=13, E=14, F=15.

Conversions from one system and another system

Conversion of decimal to binary • The easiest way to convert decimal to its binary equivalent is to use division algorithm. • Divide by two, keep track of the remainder at each step. • Put a remainder bit as 0, if that number gets divided by two. • Put a remainder bit as 1, if that number not divided by two. FIG 1.78: Example for Decimal to Binary Conversion • The binary equivalent of 67(10) is 1000011(2). Conversion of binary to decimal • Multiply each bit by 2n , where n is “weight” of bits. • The weight is position of the bit, which starts from 0 on the right, then 1 and goes on. • Add the result. E-Content of COURSE ON COMPUTER CONCEPTS (CCC) Page | 93 F 2 FIG 1.79: Example for Binary to Decimal Conversion • Decimal equivalent of 11010(2) is 26(10). Conversion of binary to hexadecimal • Group bits in fours, starting from the right. • Convert to hexadecimal digits • To convert 1011010111(2) to hexadecimal, just substitute the codes. FIG 1.80: Example of Binary to Hexadecimal Conversion • The hexadecimal equivalent of 1011010111(2) is 2C7(16) E-Content of COURSE ON COMPUTER CONCEPTS (CCC) Page | 94 F 2 Conversion of hexadecimal to binary • Convert each hexadecimal digit to a four bit equivalent binary representation. • To convert 10AF (16) to binary, just substitute the codes. FIG 1.81: Example for Hexadecimal to Binary Conversion • The Binary equivalent of 10AF (16) is 0001000010101111(2)